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Table B.1.

Spectroscopic and information of the LTE fitting of the selected lines of o-H2NCO+ and p-H2NCO+ shown in Figure 2. The frequency, the QNs, the energy of the upper level (Eu), the logarithm of the intensity (at 300 K), , and the S/N in integrated intensity of the lines are given.

Molecule Frequency QNsa Eu log Intensity b S/Nb
(GHz) (K) (nm2 MHz) (K km s−1)
o-H2NCO+ 40.122511 21, 2-11, 1 F = 1- 1 1.9 -5.0506 0.194 23
40.122797 21, 2-11, 1 F = 1- 2 1.9 -6.2267 … …
40.123224 21, 2-11, 1 F = 1 - 0 1.9 -4.9256 … …
40.123539 21, 2-11, 1 F = 3 - 2 1.9 -4.3024 … …
40.124590 21, 2-11, 1 F = 2 - 1 1.9 -4.5734 … …
40.124876 21, 2-11, 1 F = 2 - 2 1.9 -5.0505 … …
40.781503 21, 1-11, 0 F = 1 - 0 2.0 -4.9115 0.116 17
40.782899 21, 1-11, 0 F = 2 - 2 2.0 -5.0364 … …
40.783205 21, 1-11, 0 F = 3 - 2 2.0 -4.2882 … …
40.784147 21, 1-11, 0 F = 2 - 1 2.0 -4.5593 … …
40.784622 21, 1-11, 0 F = 1 - 1 2.0 -5.0364 … …
80.246416 41, 4-31, 3 F = 5 - 4 8.7 -3.3697 0.211 31
80.246532 41, 4-31, 3 F = 3 - 2 8.7 -3.6030 … …
80.246564 41, 4-31, 3 F = 4 - 3 8.7 -3.4849 … …
81.565492 41, 3-31, 2 F = 3 - 2 8.8 -3.5890 0.209 31
81.565524 41, 3-31, 2 F = 5 - 4 8.8 -3.3557 … …
81.565633 41, 3-31, 2 F = 4 - 3 8.8 -3.4709 … …
101.95584 51, 4-41, 3 F = 4 - 3 13.7 -3.0757 0.165 18
101.95585 51, 4-41, 3 F = 6 - 5 13.7 -3.1660 … …
101.95591 51, 4-41, 3 F = 5 - 4 13.7 -4.5462 … …
p-H2NCO+ 40.453210 20, 2-10, 1 F = 1 - 0 2.9 -4.8970 0.168 20
40.454746 20, 2-10, 1 F = 3 - 2 2.9 -4.1488 … …
40.454815 20, 2-10, 1 F = 2 - 1 2.9 -4.4199 … …
40.455616 20, 2-10, 1 F = 1 - 0 2.9 -4.7720 … …
40.455778 20, 2-10, 1 F = 2 - 2 2.9 -4.8970 … …
80.906908 40, 4-30, 3 F = 5 - 4 9.7 -3.3131 0.261
80.906934 40, 4-30, 3 F = 4 - 3 9.7 -3.4283 … …
80.907001 40, 4-30, 3 F = 3 - 2 9.7 -3.5464 … …
101.13112 50, 5-40, 4 F = 6 - 5 14.6 -3.0434 0.213
101.13114 50, 5-40, 4 F = 5 - 4 14.6 -3.1336 … …
101.13117 50, 5-40, 4 F = 4 - 3 14.6 -3.2251 … …
101.13223 50, 5-40, 4 F = 5 - 5 14.6 -4.5138 … …

Notes.

a

The CDMS entry accounts for the hyper-fine splitting because of the nuclear spin of 14N. Hence the QNs are presented in this way: F = F″ →  F′.

b

In our data, the hyper-fine splitting is unresolved. Thus, the S/N was calculated by the sum of the individual F″ →  F′ components.

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