Volume 567, July 2014
|Number of page(s)||10|
|Published online||07 July 2014|
The Green’s function G(r,r′,p,p′) for Eq. (1) satisfies (A.1)where G(u) ≡ G(r,r′,u,p′). In rectangular coordinates, and assuming the sources are on the Galactic plane, i.e., z′ = 0, we can write the above equation as
For z ≠ 0, Eq. (A.3) reduces to the following simple differential equation: (A.4)Solving the above equation by using the boundary condition that the particle density, and hence , vanishes at z = ± H, the solution of Eq. (A.3) for regions above (z> 0) and below (z< 0) the Galactic plane is obtained as, (A.5)where . The function can be determined using the continuity relation at z = 0 as follows. Integrating Eq. (A.3) over z around z = 0, we get
(A.6)where . Substituting for at z = 0 ±, and rearranging the terms, Eq. (A.5) reduces into a first order linear differential equation in p as (A.7)where, (A.8)The integrating factor of Eq. (A.6) is: (A.9)With this, the general solution of Eq. (A.6) is obtained as, (A.10)where we have written,
(A.11)The first term on the right hand side of Eq. (A.8) can be integrated by parts taking E(p1) as the first function and the derivative part as the second function as follows: (A.12)where H[m] is the Heaviside step function, which has the property H[m] = 1(0) for m> 0( < 0). Substituting for E(p), which is defined by Eq. (A.9), into Eq. (A.10), we get, (A.13)Imposing the boundary condition that there are no particles at p = 0, Eq. (A.11) becomes,
(A.14)In the present study, as we assume that particles are injected with a finite momentum p′ ≥ p0 where p0 is the low-momentum cutoff we have introduced so as to approximate the ionization losses (see Sect. 2), the delta function and the Heaviside step function in the first two terms on the right hand side of the above equation becomes zero. This gives I0 = 0, and the general solution of Eq. (A.6) becomes, (A.15)Proceeding further, we have,
(A.19)where we have substituted in the last expression. Analogous to Eq. (A.13), we also obtain, (A.20)Substituting Eqs. (A.16) and (A.17) into Eq. (A.12), we get (A.21)where we have written, Substituting for from Eq. (A.18) into Eq. (A.4), the Green’s function for Eq. (1) can be obtained using the relation,
© ESO, 2014
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