Open Access
Erratum
This article is an erratum for:
[https://doi.org/10.1051/0004-6361/201628955]


Issue
A&A
Volume 668, December 2022
Article Number C1
Number of page(s) 1
Section Planets and planetary systems
DOI https://doi.org/10.1051/0004-6361/201628955e
Published online 09 December 2022

In the last paragraph of Sect. 2.5 of the original paper, the treatment of the boundary condition was incorrectly described. In the original paper, we stated that r( r32)=0${\partial \over {\partial r}}\left( {\sum {{r^{{3 \over 2}}}} } \right) = 0$ was imposed at the inner and outer boundaries, r = rin = 0.01 au and = rout = 104 au, and that this condition corresponds to the zero-torque boundary condition. However, this statement and explanation were incorrect. The actual boundary condition implemented in our calculations was to impose r( r)=0${\partial \over {\partial r}}\left( {\sum r } \right) = 0$ at r = rin and = rout.

This is consistent with the zero-torque boundary condition, r2 αrϕ¯cs2${r^2}\sum {\overline {{\alpha _{r\phi }}} c_{\rm{s}}^2} $ ( r32$ \propto \sum {{r^{{3 \over 2}}}} $ for a constant αrϕ¯$\overline {{\alpha _{r\phi }}} $ and Tr12$T \propto {r^{ - {1 \over 2}}}$; see Eqs. (10) and (A.5)) → 0 at the centre, r → 0. The physical meaning of r( r)=0${\partial \over {\partial r}}\left( {\sum r } \right) = 0$ at r = rin and = rout is to impose a constant mass accretion rate induced by the stress for a constant αrϕ¯$\overline {{\alpha _{r\phi }}} $ and Tr12$T \propto {r^{ - {1 \over 2}}}$ (Eq. (33)) across the boundary. All of the results presented in the original paper remain unchanged.


© T. K. Suzuki et al. 2022

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