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Home All issues Volume 621 (January 2019) A&A, 621 (2019) A129 Full HTML
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Table A.1

C–H–O reactions.

Reaction Rate coefficient
O(3P) + H2 → OH + H k159 = 8.49 × 10−20T2.67 exp(−3160.0∕T)
O(3P) + CH3 → H2CO + H k162b = 1.4 × 10−10
O(3P) + C2H → CO + CH k164 = 1.7 × 10−11
O(3P) + C2H2 → CO + 3CH2 k165a = 1.5 × 10−11 * exp(−1600.0∕T)
O(3P) + C2H2 → HCCO + H k165b = 5 × 10−11 * exp(−1600.0∕T)
O(3P) + C2H3 → OH + C2H2 k166a = 1.25 × 10−11
O(3P) + C2H3 → CO + CH3 k166b = 1.25 × 10−11
O(3P) + C2H3 → HCO + 3CH2 k166c = 1.25 × 10−11
O(3P) + C2H3 → CH2CO + H k166d = 1.25 × 10−11
O(3P) + C2H4 → HCO + CH3 k167a = 3.45 × 10−18T2.08
O(3P) + C2H4 → H2CO + 3CH2 k167b = 1.5 × 10−19T2.08
O(3P) + C2H4 → CH2CO + H2 k167c = 1.5 × 10−19T2.08
O(3P) + C2H4 → CH3CO + H k167d = 2.0 × 10−18T2.08
O(3P) + C2H5 → H2CO + CH3 k168a = 1.7 × 10−11
O(3P) + C2H5 → CH3CHO + H k168b = 8.3 × 10−11
O(3P) + OH → O2 + H k171 = 2.3 × 10−11 exp(110.0∕T)
O(3P) + CO + M → CO2 + M k0,172 = 6.5 × 10−33 exp(−2180.0∕T)
k∞,172 = 2.66 × 10−14 exp(−1459.0∕T)
O(3P) + HCO → CO2 + H k173b = 5.0 × 10−11
O(3P) + H2CO → HCO + OH k174 = 6.9 × 10−13T0.57 exp(−1390.0∕T)
O(3P) + CH3O → O2 + CH3 k176b = 3.55 × 10−11 exp(−239.0∕T)
O(3P) + CH3OH → CH2OH + OH k177a = 3.2 × 10−19T2.5 exp(−1550.0∕T)
O(3P) + CH3OH → CH3O + OH k177b = 3.2 × 10−19T2.5 exp(−1550.0∕T)
O(3P) + HCCO → CO + CO + H k178 = 1.6 × 10−10
O(3P) + CH2CO → HCO + CO + H k179a = 1.3 × 10−12 exp(−680.0∕T)
O(3P) + CH2CO → H2CO + CO k179c = 1.3 × 10−12 exp(−680.0∕T)
O(3P) + CH3CO → CO2 + CH3 k180b = 2.4 × 10−10
O(3P) + CH3CHO → CH3CO + OH k181 = 1.8 × 10−11 exp(−1100.0∕T)
O(3P) + C2H4OH → CH3CHO + OH k182 = 1.5 × 10−10
O(1 D) → O(3 P) 6.7 × 10−3
O(1 D) + H2 → OH + H k183 = 1.5 × 10−10
O(1 D) + CH4 → OH + CH3 k184a = 1.35 × 10−10
O(1 D) + CH4 → H2CO + H2 k184b = 1.5 × 10−11
O(1 D) + H2 O → OH + OH k185 = 2.1 × 10−10
O(1 D) + CO2 → CO2 + O(3P) k186 = 7.4 × 10−11 exp(120.0∕T)
OH + H + M → H2 O + M k0,187 = 6.1 × 10−26 * T−2.0
k∞,187 = 2.69 × 10−10 exp(−75.0∕T)
OH + H2 → H2 O + H k188 = 7.7 × 10−12 exp(−2100.0∕T)
OH + CH3 → H2 O + 1CH2 k190a = 1.0 × 10−12
OH + CH3 + M → CH3 OH + M k0,191 = 6.4 × 10−29 exp(1033.0∕T)
k∞,191 = 1.44 × 10−10T0.1
OH + CH4 → H2 O + CH3 k192 = 3.9 × 10−12 exp(−1885.0∕T)
OH + C2 H → O(3 P) + C2 H2 k193a = 3.0 × 10−11
OH + C2 H2 + M → CH3 CO + M k0,194a = 2.6 × 10−26T−1.5
k∞,194a = 1.0 × 10−17T2.0
OH + C2 H3 → H2 O + C2H2 k195 = 5.0 × 10−11
OH + C2H4 + M → C2H4OH + M k0,197 = 3.34 × 10−21T−3.1
k∞,197 = 9.0 × 10−12
OH + C2H5 → O(3P) + C2H6 k198a = 1.66 × 10−40T8.8 exp(−250.0∕T)
OH + C2H5 → H2O + C2H4 k198b = 4.0 × 10−11
OH + C2H6 → H2O + C2H5 k199 = 7.8 × 10−12 exp(−1020.0∕T)
OH + OH → H2O + O(3P) k200 = 4.2 × 10−12 exp(−240.0∕T)
OH + CO → CO2 + H k201 = 2.86 × 10−13 exp(−176.∕T)
OH + HCO → CO + H2O k202 = 1.7 × 10−10
OH + H2CO → HCO + H2O k203 = 8.8 × 10−12 exp(25.0∕T)
OH + CH3OH → CH2OH + H2O k206a = 5.0 × 10−12 exp(−600.0∕T)
OH + CH3OH → CH3O + H2O k206b = 1.68 × 10−12 exp(−600.0∕T)
OH + CH2CO → H2CO + HCO k207a = 7.0 × 10−12
OH + CH2CO → CH2OH + CO k207b = 1.0 × 10−11
OH + CH3CHO → CH3CO + H2O k209 = 5.6 × 10−12 exp(310.0∕T)
H2O + CH + M → CH2OH + M k0,210 = 1.0 × 10−31
k∞,210 = 9.49 × 10−12 exp(380.0∕T)
H2O + 1CH2 + M → CH3OH + M k0,212 = 1.0 × 10−26
k∞,212 = 2.67 × 10−9T−0.7
CO + H + M → HCO + M k0,213 = 1.4 × 10−34 exp(−100.0∕T)
k∞,213 = 1.96 × 10−13 exp(−1366.0∕T)
CO + CH3 + M → CH3CO + M k0,215 = 1.26 × 10−33 exp(−1636.0∕T)
k∞,215 = 2.63 × 10−13 exp(−3007.0∕T)
HCO + H → CO + H2 k217 = 1.5 × 10−10
HCO + 3CH2 → CO + CH3 k218 = 3.0 × 10−11
HCO + CH3 → CO + CH4 k219 = 4.4 × 10−11
HCO + CH3 + M → CH3CHO + M k0,220 = 1.0 × 10−31
k∞,220 = 5.0 × 10−11
HCO + C2H3 → CO + C2H4 k222 = 1.5 × 10−10
HCO + C2H5 → CO + C2H6 k223 = 2.0 × 10−10
HCO + CH3O → CH3OH + CO k226 = 1.5 × 10−10
HCO + CH3 CO → CH3 CHO + CO k228 = 1.5 × 10−11
H2CO + H → HCO + H2 k229 = 3.8 × 10−14T1.05 exp(−1650.0∕T)
H2CO + CH → CO + CH3 k230a = 8.0 × 10−11 exp(260.0∕T)
H2CO + CH → CH2CO + H k230b = 8.0 × 10−11 exp(260.0∕T)
H2CO + CH3 → HCO + CH4 k231 = 6.8 × 10−12 exp(−4450.0∕T)
CH2 OH + H → OH + CH3 k236a = 1.6 × 10−10
CH2 OH + H → H2CO + H2 k236b = 1.0 × 10−11
CH2 OH + 3CH2 → OH + C2H4 k238a = 4.0 × 10−11
CH2 OH + CH3 → H2CO + CH4 k240 = 4.0 × 10−12
CH2 OH + C2 H3 → OH + C3H5 k243a = 2.0 × 10−11
CH2 OH + C2 H3 → H2CO + C2H4 k243b = 5.0 × 10−11
CH2 OH + C2 H5 → CH3OH + C2H4 k245b = 4.0 × 10−12
CH3 O + H → OH + CH3 k249a = 7.52 × 10−11 exp(−375.0∕T)
CH3 O + H → H2CO + H2 k249b = 3.38 × 10−11 exp(−375.0∕T)
CH3 O + 3 CH2 → H2CO + CH3 k251 = 3.0 × 10−11
CH3 O + CH3 → H2CO + CH4 k252 = 4.0 × 10−11
CH3 O + C2 H3 → H2CO + C2H4 k255 = 4.0 × 10−11
CH3 O + C2 H5 → H2CO + C2H6 k256 = 4.0 × 10−11
CH3 O + CH3 O → H2CO + CH3OH k258 = 1.0 × 10−10
CH3 O + CH3 CO → CH3 CHO + H2CO k260b = 1.0 × 10−11
CH3 O + CH3 CHO → CH3 CO + CH3OH k261 = 6.0 × 10−15
CH3 OH + H → H2 O + CH3 k262a = 1.8 × 10−17T2.1 exp(−2450.0∕T)
CH3 OH + H → CH2 OH + H2 k262b = 1.8 × 10−17T2.1 exp(−2450.0∕T)
CH3 OH + CH3 → CH3 O + CH4 k265b = 2.39 × 10−23T3.1 exp(−3490.0∕T)
CH3 OH + C2 H → CH2 OH + C2H2 k266a = 1.0 × 10−11
CH3 OH + C2 H → CH3 O + C2H2 k266b = 2.0 × 10−12
CH3OH + C2H3 → CH3O + C2H4 k267b = 2.4 × 10−23T3.1 exp(−3490.0∕T)
O2 + CH → CO + OH k269a = 2.75 × 10−11
O2 + CH → HCO + O(3P) k269b = 2.75 × 10−11
O2 + 3CH2 → CO + OH + H k270a = 1.0 × 10−12
O2 + 3CH2 → CO + H2O k270b = 4.0 × 10−13
HCCO + H → CO + 3CH2 k271 = 2.5 × 10−10
CH2CO + H → CO + CH3 k272 = 3.0 × 10−11 exp(−1700.0∕T)
CH2CO + 3CH2 → CO + C2H4 k273a = 2.1 × 10−10
CH2CO + 3CH2 → HCCO + CH3 k273b = 1.0 × 10−17
CH3CO + H → HCO + CH3 k274a = 3.57 × 10−11
CH3CO + H → CH2CO + H2 k274b = 1.92 × 10−11
CH3CO + 3CH2 → CH2CO + CH3 k275 = 3.0 × 10−11
CH3CO + CH3 → CO + C2H6 k276a = 4.9 × 10−11
CH3CO + CH3 → CH2CO + CH4 k276b = 1.0 × 10−11
CH3CO + C2H → CH2CO + C2H2 k277 = 3.0 × 10−11
CH3CHO + H → CH3CO + H2 k279 = 2.23 × 10−11 exp(−1661.0∕T)
CH3CHO + 3CH2 → CH3CO + CH3 k280 = 2.76 × 10−12 exp(−1768.0∕T)
CH3CHO + CH3 → CH3CO + CH4 k281 = 3.3 × 10−30T5.64 exp(−1240.0∕T)
CO2 + CH → HCO + CO k284 = 5.7 × 10−12 exp(−345.0∕T)
CO2 + 3CH2 → CO + H2CO k285 = 3.9 × 10−14
C2H4OH + H → CH3CHO + H2 k286 = 8.3 × 10−11
C2H4OH + CH3 → CH3CHO + CH4 k287 = 4.0 × 10−11

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