Open Access

Table A.1

Placeholder for differentiation of mass balance equations.

mass balance H2O mass balance CO2
(volatile 1) (volatile 2)
ɡ=FH2O$={{F}_{{{\text{H}}_{2}}\text{O}}}$ l = FCO2$l\text{ }\!\!~\!\!\text{ = }\!\!~\!\!\text{ }{{F}_{\text{C}{{\text{O}}_{2}}}}$
a1=MH2Omoa  (1)${{a}_{1}}=-M_{{{\text{H}}_{2}}\text{O}}^{\text{moa }\!\!~\!\!\text{ }}\text{ }\!\!~\!\!\text{ (1)}$ a2=MCO2moa  (1)${{a}_{2}}=-M_{\text{C}{{\text{O}}_{2}}}^{\text{moa }\!\!~\!\!\text{ }}\text{ }\!\!~\!\!\text{ (1)}$
b1=kH2OMcrystal ${{b}_{1}}={{k}_{{{\text{H}}_{2}}\text{O}}}\cdot {{M}^{\text{crystal }\!\!~\!\!\text{ }}}$ b2=kCO2Mcrystal ${{b}_{2}}={{k}_{\text{C}{{\text{O}}_{\text{2}}}}}\cdot {{M}^{\text{crystal }\!\!~\!\!\text{ }}}$
f = 3.44 × 10−8 (Schaefer) or 2.08 × 10−6 (E-T) v = 2.08 × 10−6 (E-T)
e =0 (Schaefer) or −3 × 10−3 (E-T) u = −5 × 10−4 (E-T)
exp1 = 1/0.74 (Schaefer) or 1/0.52 (E-T) exp2 = 1/0.45 (E-T)
w1=μCO2/μH2O${{w}_{1}}={{\mu }_{\text{C}{{\text{O}}_{2}}}}/{{\mu }_{{{\text{H}}_{2}}\text{O}}}$ w2=μH2O/μCO2${{w}_{2}}={{\mu }_{{{\text{H}}_{2}}\text{O}}}/{{\mu }_{\text{C}{{\text{O}}_{2}}}}$

Both volatile systems

h = Mliq
h=Mliq$h={{M}^{\text{liq}}}$
d=4πRPl2ɡ$d=\frac{4\pi R_{Pl}^{2}}{}$

(1) Due to numerical reasons, we add in the code implementation mass budget correction terms to a1 and a2. See Sect. D for a description and discussion of code stability and performance.

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