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Table 2
Reaction rates among hydrogen, deuterium and helium.
| Reaction | Reaction rate | Ref. | |
| (cm3/s) | |||
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| 1 | H2 + D → H + HD | if (T ≤ 2 × 103K) k1 = dex[− 56.4737 + 5.88886log (T) | a |
| + 7.196292log (T)2 + 2.25069log (T)3 | |||
|
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| if (T > 2 × 103 K) k1 = 3.17 × 10-10exp(− 5207/T) | |||
| 2 | HD + H → H2 + D | if (T ≤ 200 K) k2 = 5.25 × 10-11exp(− 4430/T) | a |
| if (T > 200K) k2 = 5.25 × 10-11exp [(− 4430/T) + (173900/T5)] | |||
| 3 | D+ + H2 → H+ + HD | k3 = 10-9 [0.417 + 0.846log (T) − 0.137 log (T)2] | a |
| 4 | H+ + HD → D+ + H2 | k4 = 1.1 × 10-9exp(− 488/T) | a |
| 5 | H+ + D → D+ + H | if (T ≤ 2 × 105 K) k5 = 2 × 10-10T0.402exp(− 37.1/T) − 3.31 × 10-17T1.48 | a |
| if (T > 2 × 105K) k5 = 3.44 × 10-10T0.35 | |||
| 6 | H + D+ → D + H+ | k6 = 2.06 × 10-10T0.396exp(− 33/T) + 2.03 × 10-9T-.332 | a |
| 7 | HD + D+ → D2 + H+ | k7 = 10-9 | a |
| 8 | H+ + D2 → D+ + HD | k8 = 2.1 × 10-9exp(− 491/T) | a |
| 9 |
|
k9 = 10A
with  , with
ai as in Table 7 |
|
| 10 | H + H+ → H2 + + γ | k10 = dex [−19.38−1.523 log (T) + 1.118 log (T)2 − 0.1269 log (T)3] | a |
| 11 |
|
k11 = 6.4 × 10-10 | a |
| 12 | H + HD+ → H2 + D+ | k12 = 10-9 | a |
| 13 | H+ + e− → H + γ | k13 = 2.753 × 10-14(315614/T)1.5 [1 + (1115188/T)0.407] -2.242 | a |
| 14 | D+ + e− → D + γ | k14 = k13 | a |
| 15 |
|
if (T ≤ 617 K) k15 = 10-8 | a |
| if (T > 617 K) k15 = 1.32 × 10-6T-0.76 | |||
| 16 | HD+ + e− → H + D | k16 = 7.2 × 10-8T-0.5 | a |
| 17 | H + e− → H− + γ | k17 = dex(− 17.845 + 0.762 log (T) + 0.1523 log (T)2 − 0.03274 log (T)3) | a |
| 18 | D + e− → D− + γ | k18 = k17 | a |
| 19 | H + e− → H+ + 2e− | k19 = exp[−32.71396786 + 13.5365560 ln(Te) − 5.73932875 ln(Te)2 | a |
| + 1.56315498 ln(Te)3 − 0.287705600 ln(Te)4 + 3.48255977 × 10-2 ln(Te)5 | |||
| −2.63197617 × 10-3 ln(Te)6 + 1.11954395 × 10-4 ln(Te)7 | |||
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| 20 | D + e− → D+ + 2e− | k20 = k19 | a |
| 21 | H− + H → H2 + e− | k21 = 10-9ξ, ξ = [0.65,5.0] , | b |
| 22 | D− + H → HD + e− | k22 = 10-9ξ/2, ξ = [0.65,5.0] | b |
| 23 | H− + D → HD + e− | k23 = k22 | b |
| 24 | D− + D → D2 + e− | k24 = k21 | b |
| 25 | H+ + D− → HD+ + e− | k25 = 1.1 × 10-9(T/300)-0.41 | a |
| 26 | D+ + H− → HD+ + e− | k26 = k25 | a |
| 27 | H− + e− → H + 2e− | k27 = exp [−18.01849334 + 2.36085220 ln(Te) − 0.282744300 ln(Te)2 | b |
| + 1.62331664 × 10-2ln(Te)3 − 3.36501203 × 10-2 ln(Te)4 | |||
| + 1.17832978 × 10-2 ln(Te)5 − 1.65619470 × 10-3 ln(Te)6 | |||
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| 28 | H− + H → 2H + e− |
|
b |
| if (Te > 0.1 eV) k28 = exp[− 20.372609 + 1.13944933 ln(Te) | |||
| −0.14210135 ln(Te)2 + 8.4644554 × 10-3 ln(Te)3 | |||
| −1.4327641 × 10-3 ln(Te)4 + 2.0122503 × 10-4 ln(Te)5 | |||
| + 8.6639632 × 10-5 ln(Te)6 − 2.5850097 × 10-5 ln(Te)7 | |||
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| 29 | H− + H+ → 2H | if (T ≤ 104 K) k29 = 2.4 × 10-6T-0.5(1 + 2 × 10-4T) | b |
| 30 |
|
|
b |
| 31 |
|
|
b |
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| 32 | H2 + e− → 2H + e− |
|
b |
| 33 | H2 + H → 3H |
|
b |
|
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| 34 | He + e− → He+ + 2e− | k34 = exp [−44.09864886 + 23.91596563 ln(Te) − 10.7532302 ln(Te)2 | b |
| + 3.05803875 ln(Te)3 − 0.56851189 ln(Te)4 + 6.79539123 × 10-2 ln(Te)5 | |||
| −5.00905610 × 10-3 ln(Te)6 + 2.06723616 × 10-4 ln(Te)7 | |||
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| 35 | He+ + e− → He + γ |
|
c |
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| 36 | He+ + e− → He + + + 2e− | k36 = exp [−68.71040990 + 43.93347633 ln(Te) − 18.4806699 ln(Te)2 | b |
| + 4.70162649 ln(Te)3 − 0.76924663 ln(Te)4 + 8.113042 × 10-2 ln(Te)5 | |||
| −5.32402063 × 10-3 ln(Te)6 + 1.97570531 × 10-4 ln(Te)7 | |||
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| 37 | He + + + e− → He+ + γ | k37 = 3.36 × 10-10T-0.5(T/1000)-0.2 [1 + (T/106)0.7] -1 | b |
Notes. More details within the text.
References. (a) Glover & Savin (2009); (b) Glover & Abel (2008); (c) Abel et al. (1997).
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