Map of emission angle for spin a = 0.98. Left: geometry of the problem with the inclination angle θ between the black hole spin axis and the line of sight, and the emission angle i between the disk normal and direction of emission of the photon in the emitter’s frame. Center and right: these maps show a map of the values of the emission angle i between the local normal to the accretion disk and the direction of photon emission for a spin of a = 0.98. The inclination angle is equal θ = 5° (center) or θ = 85° (right). The right panel can be compared to the lower left panel of Fig. 5 of García et al. (2014).