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Table 3
Tisserand functions for the spatial case in a fixed reference frame.
| F0 = 1 |
| F1 = − b′sin(u + u′) + bcos(u + u′) − a′sin(u − u′) + acos(u − u′) |
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Notes. We have u = v + ω,u′ = v′ + ω′ while a,a′,b,b′ depend on the nodes and inclinations and are given in (33).
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