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Appendix B: Segment Cox processes

We used the segment Cox point process (see Stoyan et al. 1995) to model the correlation properties of our observational samples. This process is constructed as follows: segments of length l are randomly generated inside a cube of size L (a Poisson distribution of starting points and a uniform distribution of directions in space) and Poisson-distributed points are generated along these segments. The second parameter we have to choose after l is the intensity (mean density) of segments $\lambda_{\rm S}$. Then the length density of all segments $L_{\rm V}$ is defined as

\begin{eqnarray*}L_{\rm V}=\lambda_{\rm S} L.
\end{eqnarray*}


The last parameter we have to choose in order to specify the process is the line intensity of points $\lambda_{\rm L}$. The intensity of the point process $\lambda$ is

\begin{eqnarray*}\lambda=\lambda_{\rm L} L_{\rm V}=\lambda_{\rm L}\lambda_{\rm S} l.
\end{eqnarray*}


Although this distribution of points might seem rather artificial, the good news is that the pair correlation function $\xi(r)$ for this process is known exactly (Stoyan et al. 1995):

 \begin{displaymath}\xi(r)=\left\{
\begin{array}{r@{\quad}l}
\frac{\displaystyl...
...style rl}\Big),
&x\le r_0,\\
0,&x>r_0.
\end{array} \right.
\end{displaymath} (B.1)

As we can see, the correlation function depends on r as $\xi(r)\sim(r/r_0)^{-2}$for small r. This makes it suitable for modeling observed clustering of galaxies and galaxy clusters. It does not depend on the intensity $\lambda_{\rm L}$ at all. Also, the process is homogeneous on large scales by construction. We illustrate the correlation function in Fig. B.1.


  \begin{figure}
\par\includegraphics[width=8.8cm,clip]{h1676f36.eps}\end{figure} Figure B.1: The correlation function of a segment Cox process for different correlation amplitudes.

If we want to simulate a cosmological sample, we are usually given the sample size L, the correlation length r0 and the number of objects in the sample. How do we choose the parameters $l,\lambda_{\rm S}$ and $\lambda_{\rm L}$ that describe a segment Cox process?

First, we have to choose the segment length l. It certainly has to be larger than r0 and can be chosen by the location of the first zero of the observed correlation function. Also, as seen in Fig. B.1, the smaller the ratio r0/l, the better is the approximation $\xi(r)\sim r^{-2}$. This, however, frequently gives too large a value for d. A large d means that the intensity of segments will be small and their total number $N_{\rm S}=\lambda_{\rm S} L^3$ will be small, too; we get a rather unrealistic distribution of points along a few long segments.

On the other hand, if we do not worry too much about the exact slope of the correlation function, we could choose l rather close to r0 (the upper curve in Fig. B.1). We have found that taking $l\approx1.5r_0$ works well in practice.

Let us say that we have decided to choose $l=\alpha r_0$. Then, formula (B.1) for the correlation function tells us that

\begin{eqnarray*}L_V=\frac{1}{2\pi r_0^2}\left(1-\frac{1}{\alpha}\right).
\end{eqnarray*}


We obtain for the intensity (mean density) of the segments:

\begin{eqnarray*}\lambda_{\rm S}=L_{\rm V}/d,
\end{eqnarray*}


and the last parameter $\lambda_{\rm L}$:

\begin{eqnarray*}\lambda_{\rm L}=\frac{N}{L^3 L_{\rm V}}\cdot
\end{eqnarray*}


An important point to remember when generating a segment Cox process is that having a mean number of segments $N_{\rm S}=\lambda_{\rm S} L^3$does not mean that we have to generate $N_{\rm S}$ segments. The number of segments is a Poisson-distributed random number with intensity (mean) $N_{\rm S}$, and it is useful to recall that its variance is also $N_{\rm S}$. So every realization will give us a different number of segments. The same concerns the number of points on the segments. All this combines to give us a different total number of points with every realization.


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