Table 3: Amplitudes and phases (in degrees) of the pulsation and modulation frequency components of RR Lyr from the 2004 photometric data. The values displayed in italics correspond to combination frequencies not exceeding a signal-to-noise level of 3.5. For non-combination frequencies the signal-to-noise ratio threshold is 4.0. The residuals of the fit are at 0.021 mag, which is about the noise level of the data set.
f [c/d] A [mag] $\phi$ [deg] $\Delta~\phi$ [deg]
Modulation Two-frequency Value $\Delta~A=0.00052$    
model model        
f0 1.7641704 $\pm$ 0.0000048 0.29471 25.71 0.32
2f0 3.5283407 0.13340 189.9 1.4
3f0 5.2925111 0.08794 12.6 2.14
4f0 7.0566814 0.04880 200.62 3.8
5f0 8.8208517 0.02497 33.4 7.4
6f0 10.5850221 0.01417 234.8 13.2
7f0 12.3491924 0.00806 77.7 23.2
8f0 14.1133628 0.00596 283.6 31.4
9f0 15.8775331 0.00474 112.0 39.4
10f0 17.6417035 0.00387 287.7 48.4
11f0 19.4058738 0.00355 125.5 52.8
$f_0+f_{\rm B}$ $=f_{\rm N}$ 1.7899187 $\pm$ 0.000026 0.05640 135.8 3.4
$f_0-f_{\rm B}$ $=2f_0-f_{\rm N}$ 1.7384220 0.00959 147.8 19.6
$2f_0+f_{\rm B}$ $=f_0+f_{\rm N}$ 3.5540891 0.03068 290.9 6.2
$2f_0-f_{\rm B}$ $=3f_0-f_{\rm N}$ 3.5025923 0.01427 294.6 13.2
$3f_0+f_{\rm B}$ $=2f_0+f_{\rm N}$ 5.3182594 0.03371 87.5 5.6
$3f_0-f_{\rm B}$ $=4f_0-f_{\rm N}$ 5.2667627 0.01462 131.2 12.8
$4f_0+f_{\rm B}$ $=3f_0+f_{\rm N}$ 7.0824298 0.03130 260.0 6.0
$4f_0-f_{\rm B}$ $=5f_0-f_{\rm N}$ 7.0309330 0.01048 320.5 17.8
$5f_0+f_{\rm B}$ $=4f_0+f_{\rm N}$ 8.8466001 0.02200 85.0 8.4
$5f_0-f_{\rm B}$ $=6f_0-f_{\rm N}$ 8.7951034 0.00496 187.8 37.8
$6f_0+f_{\rm B}$ $=5f_0+f_{\rm N}$ 10.6107704 0.01327 252.1 14.2
$6f_0-f_{\rm B}$ $=7f_0-f_{\rm N}$ 10.5592737 0.00285 15.9 65.6
$7f_0+f_{\rm B}$ $=6f_0+f_{\rm N}$ 12.3749408 0.00978 71.4 919.2
$7f_0-f_{\rm B}$ $=8f_0-f_{\rm N}$ 12.3234441 0.00393 176.6 47.6
$8f_0+f_{\rm B}$ $=7f_0+f_{\rm N}$ 14.1391111 0.00637 248.5 29.4
$8f_0-f_{\rm B}$ $=9f_0-f_{\rm N}$ 14.0876144 0.00302 44.0 62.0
$9f_0+f_{\rm B}$ $=8f_0+f_{\rm N}$ 15.9032815 0.00393 80.1 47.6
$9f_0-f_{\rm B}$ $=10f_0-f_{\rm N}$ 15.8517848 0.00218 225.4 85.8
$10f_0+f_{\rm B}$ $=9f_0+f_{\rm N}$ 17.6674518 0.00193 289.0 97.0
$10f_0-f_{\rm B}$ $=11f_0-f_{\rm N}$ 17.6159551 0.00309 37.8 30.3
$11f_0+f_{\rm B}$ $=10f_0+f_{\rm N}$ 19.4316222 0.00033 48.1 567.2
$11f_0-f_{\rm B}$ $=12f_0-f_{\rm N}$ 19.3801255 0.00216 214.6 86.6
$f_{\rm B}$ $=f_{\rm N}-f_0$ 0.0257483 0.00166 154.3 112.6


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