Table 3: Monte Carlo model fits.

Parameter		 L1498 L1517B Note

Core		      

$r_{\rm max}$   (cm)		 $4 \times 10^{17}$ $4 \times 10^{17}$  
$V_{\rm LSR}$   (km s-1) 7.8 5.8  
${\rm d}V/{\rm d}r\vert_{\rm in}$   (km s-1 pc-1) 0 0 (1)
${\rm d}V/{\rm d}r\vert_{\rm out}$   (km s-1 pc-1) -0.5 2.0 (1)
$r_{\rm br}$   (cm) $1.75 \times 10^{17}$ $1.5 \times 10^{17}$ (1)
$\Delta V_{\rm NT}$   (km s-1) 0.125 0.125  
Tk   (K) 10 9.5 (2)

Envelope		      

$r_{\rm max}$   (cm)		 $8 \times 10^{17}$ $8 \times 10^{17}$  
$V_{\rm LSR}$   (km s-1) 7.45 5.8  
$\Delta V_{\rm NT}$   (km s-1) 0.625 0.500  

Molecular abundances		      

X0(NH3)		 $1.4 \times 10^{-8}$ $1.7 \times 10^{-8}$ (3)
$\beta$ 3 1 (4)
X0(N2H+) $1.7 \times 10^{-10}$ $1.5 \times 10^{-10}$ (4)
X0(C18O) $0.5 \times 10^{-7}$ $1.5 \times 10^{-7}$ (5)
$r_{\rm hole}$(C18O)   (cm) $1.5 \times 10^{17}$ $1.75 \times 10^{17}$ (5)
$X_0(\mbox{CS})$ $3 \times 10^{-9}$ $3 \times 10^{-9}$ (5)
$r_{\rm hole}$(CS)   (cm) $1.0 \times 10^{17}$ $ 1.15 \times 10^{17}$ (5)
(1)
${\rm d}V/{\rm d}r = {\rm d}V/{\rm d}r\vert_{\rm in}$ if $r<r_{\rm br}$ and ${\rm d}V/{\rm d}r = {\rm d}V/{\rm d}r\vert_{\rm out}$ if $r>r_{\rm br}$.
(2)
Constant for all r.
(3)
Para-X(NH3) = X0(NH3) $(n(r)/n_0)^\beta$ with 10-9 threshold.
(4)
Constant in L1517B. For L1498, abundance drops by factor 3 at $r=1.8\times 10^{17}$ cm.
(5)
X = X0 for $r>r_{\rm hole}$ and X = 0 for $r<r_{\rm hole}$.


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