\begin{table}%t3
\caption{Results of the fits. LZ is for Liang-Zhang relation, GGL for the Ghirlanda et~al. one.} 
\label{table:no3} 
%\centering
\par
\begin{tabular}{c c c c} 
\hline\hline 
Fit & $q_0$ & $j_0 + \Omega$ & $s_0$ \\ 
\hline 
$d_{\rm l}(z)$ LZ & $-0.94 \pm 0.30$ & $2.71 \pm 1.1$ &  \\ 
$d_{\rm l}(z)$ GGL & $-0.39 \pm 0.11$ & $2.52 \pm 1.33$ &   \\
$\ln [d_{\rm l}/z]$ LZ & $-0.68 \pm 0.30$ & $0.021 \pm 1.07$ & $3.39 \pm 17.13$  \\
$\ln [d_{\rm l}/z]$ GGL & $-0.78 \pm 0.20$ & $0.62 \pm 0.86$ & $8.32 \pm 12.16$ \\
\hline 
\end{tabular}
\end{table}