\begin{table}%t1
%\centering
\par
\caption{Summary of analytic solutions for the polarisation as discussed in  Sect.~\ref{polarisation}.}\label{table_pol}
\small \begin{tabular}{lll}
\hline\hline\noalign{\smallskip}
Polarisation $\chi$ for & General expression for~$\chi$ & Approximation for $\chi$\\
\hline\noalign{\smallskip}
$T=0$&$\left(2\sum_{\nu=1}^{\frac{\mu_{\rm e}^2-m^2}{2eB}}\sqrt{1-\frac{2\nu eB}{\mu_{\rm e}^2-m^2}}+1\right)^{-1}$&${3eB}/(2\mu_{\rm e}^2)$ for $\mu_{\rm e}\gg\sqrt{2eB},m$\\
$T \gg 2eB \gg \mu, m$&$\left(3\frac{T^2}{eB}\frac{\zeta(3)}{\ln{2}}-1\right)^{-1}$&${eB\ln{2}}/(3\zeta(3)T^2)$ as $T^2 \gg 2eB$\\
$m \gg T \gg 2eB, \mu_{\rm e}=0$&$\left(\frac{2T}{eB}\frac{mK_0[m/T]+T K_1[m/T]}{K_1[m/T]}-1\right)^{-1}$&${eB}/(2mT) $ for $m \gg T$\\
$2eB \gg T \gg m, \mu$&$\left(1+\frac{4}{\ln(2)}\sqrt{\frac{\pi T}{4eB}}\exp(-\sqrt{2eB}/T) \right)^{-1}$& ... \\
\hline
\end{tabular}
\end{table}