\begin{table}%t6
\caption{\label{tab6}Fits to relations of $r_{\rm c}$ and $M_{500}$.}
\small%\centerline
{
\begin{tabular}{ccccc}
\hline
\hline\noalign{\smallskip}
 Relation  & Number of clusters & $B$ & $A$  & Comments
  \\
\hline 
$r_{\rm c}{-}M_{500}$   & 106    & $1.18 \pm 0.08 $ & $0.253 \pm 0.036 $ & ALL  \\
$r_{\rm c}{-}M_{500}$   & 52     & $0.90 \pm 0.06 $ & $0.023 \pm 0.036 $ & CCCs \\
$r_{\rm c}{-}M_{500}$   & 54     & $0.66 \pm 0.12 $ & $0.452 \pm 0.029 $ & NCCCs \\
\hline
\end{tabular}}
\smallskip
 Note: The relations are given in the form:
$ \log_{10}\left({r_{\rm c} \over 100~{\rm kpc}}\right) = A
+ B\cdot \log_{10} \left({M_{500} \over 5\times 10^{14}~{M_{\odot}}}\right)$. 
\end{table}