\begin{table}%t3
\caption{Uncertainties in the NLTE analysis of \ion{Ca}{i/ii}, where 
blanks denote NLTE theoretical equivalent widths below 5~m\AA.}
\label{corr_diff} 
%\centering
\small
\begin{tabular}{llrrrrrrrrr}
\hline\hline
 & & \multicolumn{9}{c}{changes in NLTE abundance corrections (dex)} \\
 \cline{3-11} 
\multicolumn{2}{c}{input parameter} & \ion{Ca}{i} 4226 &  4425 &  5588 & 5857 & 6162 &  6169 &  6439 & \ion{Ca}{ii} 8498 &  8927  \\
\hline
 & & \multicolumn{9}{l}{ ~~~~~~5500~K / 4.0 / $-$1} \\
Photoionization: & $\sigma_{\rm ph}$/2  &$-$0.02 & $-$0.02 & $-$0.05 & $-$0.06 & $-$0.03 & $-$0.04 & $-$0.06 &  0.00 &  0.00 \\
$e$-collisions:& $C_{ij}$(Reg)    &$-$0.02 & $-$0.01 & $-$0.03 &  0.01 &  0.00 & $-$0.02 & $-$0.02 &  0.00 &  0.14 \\
H collisions:    & \kH\ = 1        &$-$0.12 & $-$0.08 & $-$0.05 & $-$0.03 & $-$0.04 & $-$0.08 & $-$0.04 &  0.01 &  0.16 \\
\multicolumn{2}{l}{$\Delta\Vmic = +0.5$~\kms} & 0.00 & $-$0.01 & $-$0.02 &  0.00 & $-$0.02 &  0.00 & $-$0.03 &  0.00 &  0.01 \\
 & & \multicolumn{9}{l}{~~~~~~5500~K / 4.0 / $-$2} \\
Photoionization: &$\sigma_{\rm ph}$/2  &$-$0.01 & $-$0.02 & $-$0.02 & $-$0.03 & $-$0.01 & $-$0.01 & $-$0.03 &  0.00 &  0.00 \\
$e$-collisions:&$C_{ij}$(Reg)    &$-$0.04 & $-$0.01 & $-$0.03 &  0.04 &  0.00 & $-$0.01 & $-$0.02 &  0.02 &  0.08 \\
H collisions:    &\kH\ = 1        &$-$0.18 & $-$0.17 & $-$0.12 & $-$0.10 & $-$0.06 & $-$0.19 & $-$0.10 &  0.03 &  0.09 \\
\multicolumn{2}{l}{$\Delta\Vmic = +0.5$~\kms} & 0.00 &  0.00 &  0.01 &  0.00 &  0.00 &  0.00 &  0.01 & $-$0.01 &  0.00 \\
 & & \multicolumn{9}{l}{~~~~~~5500~K / 4.0 / $-$3} \\
Photoionization: &$\sigma_{\rm ph}$/2  &$-$0.01 & $-$0.01 & $-$0.01 & $-$0.02 & $-$0.01 &      & $-$0.01 &  0.00 &      \\
$e$-collisions: &$C_{ij}$(Reg)    &$-$0.03 & $-$0.01 & $-$0.03 &  0.02 &  0.00 &      & $-$0.01 &  0.07 &      \\
H collisions:    &\kH\ = 1        &$-$0.19 & $-$0.20 & $-$0.21 & $-$0.12 & $-$0.10 &      & $-$0.18 &  0.10 &      \\
\multicolumn{2}{l}{$\Delta\Vmic = +0.5$~\kms} &$-$0.01 &  0.00 &  0.00 &  0.00 & 0.00 &   &  0.00 & $-$0.03 &      \\
\hline
\end{tabular}
\end{table}