\begin{table}%T9
%\centering
\par
\caption{Scaling relations for the distant clusters.\label{tab9}}
\begin{tabular}{llll}\hline\hline
         & \multicolumn{3}{c}{$\Omega_{\rm M} = 0.3, \Omega_{\Lambda}=0.7$, 
         $z_{\rm col}=z_{\rm obs}$ }\\ \cline{2-4} 
Relation 
& $\Delta_{\rm c}=500$ 
& $\Delta_{\rm c}=500\Omega^{0.427}$ 
& $\Delta_{\rm c}=18\pi^2\Omega^{0.427}$ \\ \hline
$L_{\rm X,bol}-T$
               & $6.53^{+8.34}_{-3.82}\times10^{42} (kT)^{3.08^{+0.48}_{-0.45}}$ 
               & $7.94^{+8.92}_{-4.58}\times 10^{42}(kT)^{3.01^{+0.47}_{-0.42}}$ 
               & $1.07^{+1.26}_{-0.55}\times 10^{43}(kT)^{2.92^{+0.40}_{-0.43}}$ \\
$M-T$ 
               & $1.64^{+0.35}_{-0.26}\times10^{13} (kT)^{1.68^{+0.10}_{-0.11}}$
               & $2.07^{+0.35}_{-0.43}\times 10^{13}(kT)^{1.68^{+0.13}_{-0.08}}$ 
               & $3.31^{+0.73}_{-0.60}\times 10^{13}(kT)^{1.69^{+0.11}_{-0.11}}$ \\
$M_{\rm gas}-T$  
               & $2.88^{+0.93}_{-0.64}\times10^{12} (kT)^{1.85^{+0.14}_{-0.15}}$
               & $4.32^{+1.28}_{-0.89}\times 10^{12}(kT)^{1.80^{+0.13}_{-0.15}}$ 
               & $1.10^{+0.29}_{-0.25}\times 10^{13}(kT)^{1.67^{+0.15}_{-0.13}}$ \\
$f_{\rm gas}-T$ 
               & $0.28^{+0.09}_{-0.06}(kT)^{-0.08^{+0.14}_{-0.14}}$ 
               & $0.33^{+0.10}_{-0.08}(kT)^{-0.11^{+0.15}_{-0.15}}$
               & $0.47^{+0.16}_{-0.15}(kT)^{-0.19^{+0.20}_{-0.16}}$\\    \hline
$E_z^{-1}L_{\rm X,bol}-T$ 
               & $5.50^{+7.92}_{-3.24}\times10^{42} (kT)^{3.12^{+0.51}_{-0.48}}$
               & $7.24^{+9.15}_{-4.04}\times 10^{42}(kT)^{3.00^{+0.45}_{-0.45}}$
               & $1.01^{+0.99}_{-0.55}\times 10^{43}(kT)^{2.89^{+0.43}_{-0.39}}$ \\
$E_zM-T$ 
               & $1.73^{+0.36}_{-0.32}\times10^{13} (kT)^{1.71^{+0.11}_{-0.10}}$
               & $2.11^{+0.45}_{-0.37}\times 10^{13}(kT)^{1.73^{+0.11}_{-0.11}}$
               & $3.51^{+0.75}_{-0.62}\times 10^{13}(kT)^{1.71^{+0.11}_{-0.10}}$ \\
$E_zM_{\rm gas}-T$ 
               & $3.05^{+0.94}_{-0.72}\times10^{12} (kT)^{1.88^{+0.15}_{-0.15}}$
               & $4.62^{+1.18}_{-1.04}\times 10^{12}(kT)^{1.82^{+0.15}_{-0.12}}$
               & $1.19^{+0.30}_{-0.28}\times 10^{13}(kT)^{1.68^{+0.15}_{-0.12}}$ \\ \hline
\end{tabular}
\end{table}