\begin{table}%t5
    %\centering
\par
       \caption{As Table~\ref{table3} for the automatic method (with the height
       correction). $n=1495$.
       \label{table5} }
        \begin{tabular}{llll}
        \noalign{\smallskip}
             \hline\hline
             \noalign{\smallskip}
$A \pm M_A$        & $-B \pm M_B$    & $-C \pm M_C$    & Remark         \\
             \noalign{\smallskip}
             \hline
             \noalign{\smallskip}
14.677 $\pm$ 0.033 & 3.10 $\pm$ 0.14 & 0               & $C=0$     \\
14.549 $\pm$ 0.043 & 1.43 $\pm$ 0.38 & 2.75 $\pm$ 0.58 & $B \ne C$ \\
14.591 $\pm$ 0.030 & 1.94 $\pm$ 0.08 & 1.94 $\pm$ 0.08 & $B=C$     \\
            \hline
        \end{tabular}
   \end{table}